IXL - Minimum and maximum area and volume (Algebra 1 practice)

The rectangle below is labeled with its measured dimensions. Taking measurement error into account, what are the minimum and maximum possible areas?

16 yd

8 yd

If necessary, round your answers to the nearest thousandth.

Minimum possible area = yd²

Maximum possible area = yd²

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question

The rectangle below is labeled with its measured dimensions. Taking measurement error into account, what are the minimum and maximum possible areas?

6 yd

2 yd

If necessary, round your answers to the nearest thousandth.

Minimum possible area = yd²

Maximum possible area = yd²

key idea

To find the minimum possible area, subtract the greatest possible error from each measurement before calculating.

To find the maximum possible area, add the greatest possible error to each measurement before calculating.

solution

You want to find the minimum and maximum area, taking measurement error into account.

First find the greatest possible error. Each measurement was made to the nearest whole yard, so the greatest possible error is half of 1 yard, which is 0.5 yards.

To find the maximum possible area, add the greatest possible error to each measurement, then multiply.

A_max

L_maxW_max

Add
the
greatest
possible
error,
0.5

(6 + 0.5)(2 + 0.5)

Add
the
greatest
possible
error,
0.5

(6.5)(2.5)

16.25

To find the minimum possible area, subtract the greatest possible error from each measurement, then multiply.

A_min

L_minW_min

Subtract
the
greatest
possible
error,
0.5

(6 − 0.5)(2 − 0.5)

Subtract
the
greatest
possible
error,
0.5

(5.5)(1.5)

8.25

The
minimum
possible
area
is
8.25
square
yards,
and
the
maximum
possible
area
is
16.25
square
yards.

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Work it out

Not feeling ready yet? These can help:

D.5Greatest possible error

GG.2Area of rectangles and squares

HH.1Volume of cubes and rectangular prisms

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