Look at the table of values for the functions and
f
(
x
)
=
(
x
+
2
)
2
–
3
g
(
x
)
=
x
+
1
.x | f ( x ) | g ( x ) |
– | – | – |
– | – | 0 |
| 0 | 1 | 1 |
| 1 | 6 | 2 |
| 2 | 13 | 3 |
Based on the values in the table, where does the equation have a solution?
f
(
x
)
=
g
(
x
)
x
=
–
between 1 and
x
=
–
x
=
0
x
=
0
between and
x
=
0
x
=
1
ref_doc_title.
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